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3x^2+5x=68
We move all terms to the left:
3x^2+5x-(68)=0
a = 3; b = 5; c = -68;
Δ = b2-4ac
Δ = 52-4·3·(-68)
Δ = 841
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{841}=29$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-29}{2*3}=\frac{-34}{6} =-5+2/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+29}{2*3}=\frac{24}{6} =4 $
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